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x^2-0.05x-1.8*10^-10=0
We add all the numbers together, and all the variables
x^2-0.05x=0
a = 1; b = -0.05; c = 0;
Δ = b2-4ac
Δ = -0.052-4·1·0
Δ = 0.0025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.05)-\sqrt{0.0025}}{2*1}=\frac{0.05-\sqrt{0.0025}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.05)+\sqrt{0.0025}}{2*1}=\frac{0.05+\sqrt{0.0025}}{2} $
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